oh ic... roman numerals....

Z question was the easiest as i expected and many players were very close to reveal Z. You get letters M, I, X according to the alphabet. All of them are Roman numerals. But has anyone heard actually answers to each question are not X, Y or Z itself but coords you must go to in order to get X, Y and Z? I got plenty of answers it's 1009. Is it coords? It doesn't look so. While 1000:1:10 does. There was a ship whose digital name was Z. Y and X were also simply names of a ship.

Sliu got nearest to reveal Y
(32676*2)^3 - the most primitive solution i used to get. Question with such answer wouldn't participate in 5M T sharing, would it?
Basically we have:
+32767
0
-32768
I understand it might happen to miss 0 calculating the lenght of each axe, but isn't it lazyness not to check whether + and - lenghts are equal?

So the lenght of each axe would be 32767+1+32768=65536. Then the numbers of available coords should be 65536^3=281474976710656. It's a bit annoying when people can't read "jump there" and think Y should be 49767

Unfortunatelly when you go to 28147:49767:10656 you find nothing there. Cubing the lenght of axe wouldn't be worth 1.67M T, would it?

Some players noticed there's a small trick with max coords. You can prolong the basic maximum or minimum of each axe moving a ship manually by 1 parsec. But only one axe at a time. Means you can go to 32768:32767:32767 but can not to 32768:32768:32767 and so on. So you can prolong each axe by 2 parsecs (by 1 at each end) while others stay with a choice of 65536. Then the number of available coords is 65536^3+2*65536*65536+65536*2*655636+65536*65536*2=65536^3+6*65536^2=281500746514432. You go to 28150:7465:14432 and find a ship there with digital name (Y).

X should have looked the most difficult since it required to gather information from other players about my hws. But even if you failed to do this and were not willing to spend 2M there still was a chance to get the answer.

It took me 35 probes to get all bz coords (matched with the number other players got). It was clear the sum of digits should be among 3;6;9;12;15;18;21;24;27;30;33;36;39;42;45;48 since my hws are in 3x systems as mentioned. Calculating sums of digits in bz you get:
3x0 planets
6x0
9x2
12x0
15x1
18x1
21x2
24x6
27x6
30x6
33x4
36x3
39x2
42x0
45x0
48x0

This means number of hws i have is not 3;6;12;42;45;48 for sure. Nor 15 or 18 since single planets do not create any distance. Nor 9;21 or 39 since we get only one distance between two planets but we need to form coords. And there's actually "find distances" in the task.

So we have 24x6; 27x6; 30x6; 33x4; 36x3 left. We get 6x5/2=15 distances if i have 24, 27 or 30 hws. Or 4x3/2=6 distances if i keep 33 hws. I don't know myself how to form coords of 15 or 6 numbers. A lot of combinations. While we have exactly 3 distances if i keep 36 hws to form coords (distances were 180, 190 and 195). 6 combinations are easy to check, i even simply put them in ascending order. There stood a ship at 180:190:195 with X as a name.

A ship to destroy was at X:Y:Z as mentioned.

I doubt this was too difficult for a sum of 5M T but i'll try to introduce something easier for smaller prize the next time.

__________________________
I will defeat you. When you grow up, if you still feel raw about it, i'll be waiting.

Have i just beaten the record of post lenght?

__________________________
I will defeat you. When you grow up, if you still feel raw about it, i'll be waiting.

nope prof still holds that record

__________________________
It's allways been my fault

ahhh it was a 1000:1:10 lmfao i was trying 10:0:9 lol silly me lmfao

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Wisdom is the knowledge gained through your own mind, intelligence is knowledge passed on by anothers

The Falling Fist

I'm a Priest God never paid

Never avoid temptation, as you get older, IT will avoid you.

"You can prolong the basic maximum or minimum of each axe moving a ship manually by 1 parsec. But only one axe at a time. Means you can go to 32768:32767:32767 but can not to 32768:32768:32767 and so on. So you can prolong each axe by 2 parsecs (by 1 at each end) while others stay with a choice of 65536. "

As I expected, there was a mistake in that question... As you can go to 32768:32768:32767 manually.

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Country music, whiskey and OK

i agree with filas if you manually move diagonally, you can move 1 parasec on the x and y coordinates similtaneously.

manually you can go to these coords
32768:32767:32767 -32769:-32768:-32768
32767:32768:32767 -32768:-32769:-32768
32767:32767:32768 -32768:-32768:-32769
32768:32768:32767 -32769:-32769:-32768

can't go

32768:32767:32768 -32769:-32768:-32769
32767:32768:32768 -32768:-32769:-32769
32768:32768:32768 -32769:-32769:-32769

according to my calculating the all available coords are

65538x65538x65538-(65538x4+65536x4)=28150 07467 76576

My sincere apologies. What a shame
Next time when you seek for a ship include coords "if Rukna made a mistake here... "

__________________________
I will defeat you. When you grow up, if you still feel raw about it, i'll be waiting.